when brakes are applied to a bus, the retardation produced is 25 cm s^-2 and the bus takes 20 second to stop calculate the initial velocity of the bus and the distance travelled by bus during this time

a = 25 cm/s² 

v = 0

t = 20 s 

v = u + at 

0 = u + (-25) x (20) 

u = 500 cm/s 

Initial velocity, u = 500 cm/s 

 

s = ut + (1/2) at² 

s = (500) (20) + (1/2)  (-25) (20)² 

s = 10000 + (-5000)

s = 5000 cm = 50 metres

Distance travelled by bus after applying brakes is 50 metres.