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ICSE Class 9 Answered

plz solve urgently dear experts :
Asked by savitamahajan202 | 09 Jul, 2022, 12:47: PM
Expert Answer

Equations are to be applied is "v = u - a×t " and "S = u×t - (1/2)×a×t2 "
v is final velocity, u initial velocity, a is retardation, S is distance travelled and t is time.
 
initial velocity = 36 km/h ×(5/18) = 10 m/s
 
(1) retardation :-  0 = 10 - a×2 , solving for a  we get  retardation a = -5 m/s2  
 
(2) distance :- S = 10×2 -(1/2)×5×4 = 10 m

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