CBSE Class 11-science Answered
What is the volume of O2 (g) required at STP for the oxidation of 1L of SO2(g) at 298K and 1atm ?
2SO2(g) + 2O2(g) -> 2SO3 (g)
Asked by nisharameshkv | 16 Apr, 2020, 12:23: AM
Expert Answer
At STP,
One mole=22.4 L
So according to stoichiometry of the equation,
1 mole of O2 is required for the oxidation of 1 mole of SO2. (From stoichiometric ratio )
Which means for 22.4 L of SO2, O2 is needed=22.4L
So for oxidation of 1 L of SO2, O2 is needed= 1 L
Answered by Ravi | 16 Apr, 2020, 06:04: PM
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