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Two spherical conductors A and B are having charge densities  σA and  σB respectively. If they are joined by a thin wire then what will be the ratio of charge densities finally if the radii are rA and rB.
Asked by hitanshu04 | 17 May, 2021, 09:09: PM
Charged spherical conductors are joined by thin wire , then they are at same potential.

K × ( qA / rA ) = K × ( qB / rB ) .........................(1)

where K = 1 / ( 4 π εo ) is Coulomb's constant, qA is charge on sphere-A , qB is charge on sphere-B,

rA is radius of sphere-A and rB is radius of sphere-B .

Hence from eqn.(1) , we get ,

...........................(2)

if and are charge densities respectively on sphere-A and sphere-B after connetcing by thin wire ,

then we have ,
Hence we get ,

Answered by Thiyagarajan K | 17 May, 2021, 11:13: PM
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