CBSE Class 11-science Answered
The wavelength of an electron revolving in the 3rd orbit of Be3+ is 'x' . The radius of first Bohr orbit in H atom is k , then 'x' is equal to ?
Asked by arunavamitra50 | 18 Jun, 2018, 18:39: PM
Given:
Wavelength of an electron = x' .
The radius of first Bohr orbit i= k
n= 3
![We space have comma
straight r subscript straight n space end subscript equals space straight n squared straight r subscript 1
straight r subscript 3 space equals open parentheses 3 close parentheses squared straight r subscript 1
straight r subscript 3 space equals 9 straight r subscript 1
straight r subscript 1 space equals space straight k space...... space open parentheses given close parentheses
straight r subscript 3 space equals 9 straight k subscript 1
mνr space equals space fraction numerator nh over denominator 2 straight pi end fraction space
mν 9 straight k equals fraction numerator 3 straight h over denominator 2 straight pi end fraction
straight h over mν equals space 6 πk
straight h over mν equals space straight lambda
straight lambda equals space straight x
straight x equals 6 πk](https://images.topperlearning.com/topper/tinymce/cache/7e7a4500c192f556cb891a5034bd3076.png)
Wavelenght x =6∏k
Answered by Varsha | 21 Jun, 2018, 12:57: PM
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