The wavelength of an electron revolving in the 3rd orbit of Be3+ is 'x' . The radius of first Bohr orbit in H atom is k , then 'x' is equal to ?

Asked by arunavamitra50 | 18th Jun, 2018, 06:39: PM

Expert Answer:

Given:
 
Wavelength of an electron = x' .

The radius of first Bohr orbit i= k 
 
n= 3
 
We space have comma

straight r subscript straight n space end subscript equals space straight n squared straight r subscript 1

straight r subscript 3 space equals open parentheses 3 close parentheses squared straight r subscript 1

straight r subscript 3 space equals 9 straight r subscript 1

straight r subscript 1 space equals space straight k space...... space open parentheses given close parentheses

straight r subscript 3 space equals 9 straight k subscript 1

mνr space equals space fraction numerator nh over denominator 2 straight pi end fraction space

mν 9 straight k equals fraction numerator 3 straight h over denominator 2 straight pi end fraction

straight h over mν equals space 6 πk

straight h over mν equals space straight lambda

straight lambda equals space straight x

straight x equals 6 πk
Wavelenght x =6∏k

Answered by Varsha | 21st Jun, 2018, 12:57: PM