The no. of quanta of radiation of frequency 4.98*10^14 s^-1 required to melt 100 g of ice are(latent heat of melting of ice is 33 joule per gram)

Asked by Anil | 20th Jun, 2017, 10:56: AM

Expert Answer:

Dear anilbhat32@gmail.com

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1 g requires 33 J
So, 100 g will require 3300 J heat.
Total quanta = E = hv = 6.62 x 10-34 x 4.98 x 1014 = 32.97 x 10-20  
100 g of ice will require = 3300 / 32.97 x 10-20  = 100.09 approx 100 quanta.


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Answered by Arvind Diwale | 20th Jun, 2017, 03:57: PM