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CBSE Class 11-science Answered

The mass of 1.5055 ×10^ 23 Co molecules is is
Asked by arushidabhade | 24 May, 2019, 10:09: PM
answered-by-expert Expert Answer
We know that
 
 
1 space mole space of space CO space have equals 6.022 cross times 10 to the power of 23 space molecule These space 6.022 cross times 10 to the power of 23 space molecules space will space have equals space 28 space straight g space So comma space 1 space moleculule space will space have equals fraction numerator 28 over denominator 6.022 cross times 10 to the power of 23 end fraction space straight g 1.5055 cross times 10 to the power of 23 space end exponent space molecules space will space have equals fraction numerator 28 over denominator 6.022 cross times 10 to the power of 23 end fraction cross times 1.5055 cross times 10 to the power of 23 space end exponent space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 7 space space straight g
Answered by Ravi | 25 May, 2019, 11:46: PM

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