The kinetic energy of an object of mass m,moving with a velocity of 5m/s is 25 J.What will be its kinetic energy when its velocity is doubled?What will be its kinetic energy when its velocity is increased three times?
Asked by | 4th Dec, 2012, 04:26: PM
Expert Answer:
the K.E(KINETIC ENERGY) of the object is 25 J.
So,
25=1/2*m*(5)2
Therefore,m=2 kg.
Now, when the velocity is doubled, velocity becomes=2*5=10 m/s(ms-1)
So,
K.E.=1/2*2*(10)2 =100 J.
Now,when the velocity is increased three times,the velocity will be=3*5=15m/s
Therefore,K.E.=1/2*2*(15)2 = 225 J.
the K.E(KINETIC ENERGY) of the object is 25 J.
So,
25=1/2*m*(5)2
Therefore,m=2 kg.
Now, when the velocity is doubled, velocity becomes=2*5=10 m/s(ms-1)
So,
K.E.=1/2*2*(10)2 =100 J.
Now,when the velocity is increased three times,the velocity will be=3*5=15m/s
Therefore,K.E.=1/2*2*(15)2 = 225 J.
Answered by | 6th Dec, 2012, 03:28: PM
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