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the force between two charges at distance r is f what will be the force between these charges if the distance between them is doubled and charges are placed in a medium of dielectric constant 10 ?
Force between two charges q1 and q2 that are separated by a distance r is given as

where K = 1/(4) is Coulomb's constant and  is permittivity of free space

If distance is doubled and charges are placed in a medium of dielectric constant εr = 10 , then force F is given as

Hence Force F between same charges after doubling distance and placed in a medium of
dielectric constant 10 decreases by a factor (1/40) in comparison with initial force f

Answered by Thiyagarajan K | 23 Jul, 2021, 07:13: PM

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