the escape velocity of a projectile is 11.2 km/s.a body is projected out with thrice this speed .what is the speed of the body far away from the earth?

Asked by Sneha Kashyap | 25th Nov, 2013, 12:40: PM

Expert Answer:

We will use the principle of conservation of energy.
The initial kinetic energy is K.E1 = ½mv2.
The kinetic energy far away from earth is = K.E2 = ½mv'2
 
The initial potential energy on earth's surface is P.E1 = -GMm/R
The final potential energy far away from earth is zero.
 
Thus, using the conservation of energy we have
 

Answered by Romal Bhansali | 26th Nov, 2013, 10:20: AM

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