CBSE Class 11-science Answered
The decomposition of a certain mass of CaCO3 gave 11.2 dm3 of CO2 gas at STP . The mass of KOH required to completely neutralise the gas is
a) 56g
b) 28g
c) 42g
d)20g
Asked by Balbir | 21 Jun, 2019, 09:57: PM
Expert Answer
Given:
Volume of CO2 = 11.2 dm3
We have,
1 mole of CO2 = 22.4 dm3
44 gm of of CO2 = 22.4 dm3
x gm of CO2 = 11.2 dm3
x =
The neutralisation reaction is as,
56 gm KOH required for neutralisation of 44 gm of of CO2
KOH required for neutralisation of 22 gm of of CO2
28 gm of KOH is required for complete neutralisation of 22 gm of of CO2.
Answered by Varsha | 23 Jun, 2019, 10:32: PM
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