The base of an equilateral triangle with side 2a lies along the y-axis such that the mid-point of the base is at the origin.find vertices of the triangle.

Asked by  | 1st Oct, 2010, 01:28: PM

Expert Answer:

Dear student,
here's the answer.
ATQ,
the coordinates of the vertex on the y axis are (0,a) and (0,-a)
since the mid point of the base is at the origin, so the perpendicular bisector of the base has to pass thru the origin and must lie along the x axis.9at right angles to the base)
so if BC is the base and A is the third  vertex, then coordinates of A must be (a,0) or( -a,0)..using the distance formula and the given info that side of the triangle=2a
so the vertices are
(0,a),(0,-a),(a,0)
or
(0,a)(0,-a),(-a,0)

Answered by  | 1st Oct, 2010, 07:15: PM

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