CBSE Class 11-science Answered
Questions 21
Asked by Poojaguptaindia52 | 08 Mar, 2020, 01:13: PM
Expert Answer
We have equation of motion that relates distance S travelled in time t as, " S = u t - (1/2) g t2 "
if t1 and t2 are the times for travelling same vertical distance h, then we have
h = u t1 - (1/2) g t12 = u t2 - (1/2) g t22 ................(1)
where u is initial velocity
from eqn.(1), we get , u ( t1 - t2 ) = (1/2) g [ t12 - t22 ] or u = (g/2) [ t1 + t2 ] ............. (2)
we get , time to reach maximum height as , ( u/g ) = (1/2) [ t1 + t2 ]
Answered by Thiyagarajan K | 08 Mar, 2020, 04:35: PM
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