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CBSE Class 11-science Answered

Questions 21
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Asked by Poojaguptaindia52 | 08 Mar, 2020, 01:13: PM
answered-by-expert Expert Answer
We have equation of motion that relates distance S travelled in time t as,  " S = u t - (1/2) g t2 "
 
if t1 and t2 are the times for travelling same vertical distance h, then we have
 
h = u t1 - (1/2) g t12 = u t2 - (1/2) g t22 ................(1)
 
where u is initial velocity
 
from eqn.(1), we get ,  u ( t1 - t2 ) = (1/2) g [ t12 - t22 ]    or    u  = (g/2) [ t1 + t2 ] ............. (2)
 
we get , time to reach maximum height as  ,   ( u/g ) = (1/2) [ t1 + t2 ]
 
Answered by Thiyagarajan K | 08 Mar, 2020, 04:35: PM
CBSE 11-science - Physics
Asked by rustampathan | 25 Feb, 2024, 06:39: PM
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CBSE 11-science - Physics
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Asked by hjha9709 | 25 Feb, 2024, 12:13: PM
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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