CBSE Class 11-science Answered

Let u be the initial projection speed and θ be the initial projection angle of shoot .

Vertical displacement h after time duration t from initial time of projection is

h = ( u sinθ ) t - (1/2) g t²  .......................(1)

Horizontal  displacement x after time duration t from initial time of projection is

x = ( u cosθ ) t .........................(2)

From the given information of height h of tower and distance x of projection point from foot of tower ,

we can use only equations (1) and (2) .

But we have three unknowns u , θ and t . There is no way to get third equation .

Hence this question can not be solved .