Q

Asked by araima2001 | 9th Sep, 2016, 11:08: AM

Expert Answer:

begin mathsize 12px style The space cordinates space of space centre space of space mass space is space
top enclose straight x equals fraction numerator integral subscript 0 superscript straight a straight x space straight f open parentheses straight x close parentheses space dx over denominator integral subscript 0 superscript straight a space straight f open parentheses straight x close parentheses space dx end fraction
top enclose straight x equals fraction numerator integral subscript 0 superscript straight a straight x space kx squared space dx over denominator integral subscript 0 superscript straight a space kx squared space dx end fraction space....... left parenthesis Here comma space straight f open parentheses straight x close parentheses equals space kx squared right parenthesis
top enclose straight x equals fraction numerator integral subscript 0 superscript straight a straight x cubed space dx over denominator integral subscript 0 superscript straight a space straight x squared space dx end fraction
top enclose straight x equals open square brackets fraction numerator 3 straight x to the power of 4 over denominator 4 straight x cubed end fraction close square brackets subscript 0 superscript straight a
rightwards arrow top enclose straight x equals fraction numerator 3 straight a to the power of 4 over denominator 4 straight a cubed end fraction
rightwards arrow top enclose straight x equals fraction numerator 3 straight a over denominator 4 end fraction end style

Answered by Yashvanti Jain | 9th Sep, 2016, 04:15: PM