CBSE Class 11-science Answered
Plz solve it fast
Asked by rajdhan.yadav187350 | 02 Oct, 2018, 13:30: PM
Expert Answer
if the 20N force is acting towards north on a 10 kg mass, then acceleration is 20/10 = 2 m/s2 .
displacement Sn in north direction after 2 sec will be determined by the formula Sn = (1/2)×a×t2 ,
since initial velocity towards north direction is zero. a is acceleration and t is time.
Sn = (1/2)×2×22 = 4 m/s
velocity component along east direction is unaffected. hence displacement Se in east direction after 2 second is given by, Se = 2×2 = 4 m/s
resultant displacement as shown in figure = 4√2 m/s
Answered by Thiyagarajan K | 03 Oct, 2018, 01:10: AM
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