Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

Pls solve.

Asked by pb_ckt | 18 May, 2019, 11:05: PM
Expert Answer
Option (2) is correct.
 
Given:
 
For H2SO4 
 
M1 = 0.2 M
 
V1 = 100 ml
     = 0.1 litre
 
No. of moles of H2SO4 =  0.2 × 0.1 
 
                                 = 0.02 moles
 
For NaOH
 
M2 = 0.5 M
 
V2 = 100 ml
    = 0.1 litre
 
No. of moles of NaOH = 0.5× 0.1 
 
                               = 0.05 moles
We know,
 
straight H subscript 2 SO subscript 2 space space space space plus space space space space 2 NaOH space space rightwards arrow with space space space space space on top space space 2 Na subscript 2 SO subscript 4 space space space plus space space straight H subscript 2 straight O
1 space mol space space space space space space space space space space space space space 2 space mol space space space space space space space space space space space space space space space 2 space mol space space space space space space space space space space space space 1 space mol space space space space space space space space
 
 
So, here H2SO4 acts as limiting reagent.
 
Therefore, 0.02 moles of H2SO4 will give,
 
 
1 space mole space of space straight H subscript 2 SO subscript 4 space gives space 1 space moles space of space Na subscript 2 SO subscript 4

0.02 space mole space of space space straight H subscript 2 SO subscript 4 space will space give space fraction numerator 1 cross times 0.02 over denominator 1 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.02 space moles space of space Na subscript 2 SO subscript 4

Weight space of space Na subscript 2 SO subscript 4 space equals space Molecular space mass space cross times space No. space of space moles

space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 142 cross times space 0.02

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 2.84 space gm
 
Mass of salt produced is 2.84 gm.
Answered by Varsha | 20 May, 2019, 03:14: PM
CBSE 11-science - Chemistry
Asked by mallikarjunasangi28 | 22 Jul, 2022, 07:57: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by vedwatisharma79 | 10 Jun, 2022, 05:27: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by thathvakunjusree | 10 Dec, 2021, 06:46: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by udheshraddha2004 | 28 Oct, 2021, 09:37: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by arunparewa2000 | 27 Oct, 2021, 06:59: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by arttameher038 | 23 Aug, 2021, 07:06: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by ishaansax007 | 07 Jun, 2021, 04:36: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by ebinoji | 20 Dec, 2020, 06:28: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by pamaurya76 | 27 Aug, 2020, 05:06: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by harsh.mangla.2003 | 03 Jul, 2020, 04:55: PM
ANSWERED BY EXPERT
Season Break Offer!
Get 60% Flat off instantly.
Avail Now
×