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CBSE Class 11-science Answered

Pls solve.
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Asked by pb_ckt | 18 May, 2019, 11:06: PM
answered-by-expert Expert Answer
Option (1) is correct.
 
Given:
 
Molecular mass of NH3 = X1
 
Molecular mass of N2 = X2
 
Equivalent weight of  NH3 = Y1 
 
Equivalent weight of  N2 = Y2
 
We know
 
Change in oxidation number of N in  NH3 = 3
 
Change in oxidation number of each N atom in N2 = 6
 
Equivalent space weight space of space NH subscript 3 space end subscript equals straight Y subscript 1 equals space straight X subscript 1 over 3

Equivalent space weight space of space straight N subscript 2 space end subscript equals straight Y subscript 2 space equals space straight X subscript 2 over 6

therefore space open parentheses straight Y subscript 1 minus bold Y subscript bold 2 bold space close parentheses space equals space straight X subscript 1 over 3 minus straight X subscript 2 over 6

space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 6 straight X subscript 1 minus 3 straight X subscript 2 over denominator 18 end fraction

space space space space space space open parentheses straight Y subscript 1 minus straight Y subscript 2 bold space close parentheses space equals space fraction numerator 2 straight X subscript 1 minus straight X subscript 2 over denominator 6 end fraction
Answered by Varsha | 20 May, 2019, 04:50: PM
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