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CBSE Class 11-science Answered

Pls solve it.
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Asked by pb_ckt | 07 Jun, 2019, 01:42: PM
answered-by-expert Expert Answer
velocity of particle after 4 seconds , v = u- (a×t)  = 45 - 10×4 = 5 m/s
 
Hence distance travelled in 5th second,  S = u×t - (1/2)a×t2 = 5×1 -(1/2)×10×1 = 0 m
Answered by Thiyagarajan K | 07 Jun, 2019, 02:25: PM
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