CBSE Class 11-science Answered
Pls solve it.
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Asked by pb_ckt | 07 Jun, 2019, 13:42: PM
velocity of particle after 4 seconds , v = u- (a×t) = 45 - 10×4 = 5 m/s
Hence distance travelled in 5th second, S = u×t - (1/2)a×t2 = 5×1 -(1/2)×10×1 = 0 m
Answered by Thiyagarajan K | 07 Jun, 2019, 14:25: PM
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