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Pls solve it.

Asked by pb_ckt | 16 May, 2019, 03:44: PM
The correct option is (2)

Given:

2 moles of each N2 , H2 and NH3 is present.

Initial weight of N2 = ?

Initial weight of H=?

The reaction is,

Now, it is given that 2 moles of NH3 is formed.
From reaction it is clear that, to produce 2 moles of NH3 1 mole of N2 and 3 H2 moles of are required.

Also it is geven that 2 moles of N2 and H2 are remained after formation of NH3.

Therefore the initial mole of  N2 = 2+1

= 3 mole
We know,

1 mole of N2 = 28 gm

3 moles of  of N2 =84 gm

Now
the initial mole of   H2= 3+2

= 5 mole

We know,

1 mole of H2 = 2 gm

5 moles of  of  H2 =10 gm

Therefore the initial weight of  N2 and H2 is 84 gm and 10 gm respectively.
Answered by Varsha | 17 May, 2019, 11:16: AM

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