CBSE Class 12-science Answered
Please solve question 2
And question 4.
![question image](https://images.topperlearning.com/topper/new-ate/topr_4082878242169142IMG20200421100518.jpeg)
Asked by abhitailor158 | 21 Apr, 2020, 10:07: AM
Single phase transformer,
E1=V1 = 3300 V
E2 = V2 = 220 V
f =50 Hz
Secondary full load current, I2 = 180 A
Number of secondary turns, N2 = 50
a) Number of primary turns,
![N subscript 1 space end subscript equals space N subscript 2 space cross times space E subscript 1 over E subscript 2 space
therefore space N subscript 1 space end subscript space equals 50 cross times space 3300 over 220 space equals space 750 space](https://images.topperlearning.com/topper/tinymce/cache/4ca3d63a0dd02b487dcfecfe686343cb.png)
Thus, number of primary turns are 750
b) The full load primary current,
![W e space k n o w comma space
f u l l space l o a d space s e c o n d a r y space c u r r e n t space
I subscript 2 space equals space 180 space A space space
I subscript 1 space equals space ?
I subscript 1 over I subscript 2 space equals space N subscript 2 over N subscript 1 space
therefore I subscript 1 space space equals space N subscript 2 over N subscript 1 cross times I subscript 2 space equals space fraction numerator 50 cross times 180 over denominator 750 end fraction equals 9000 over 750 equals space 12 space A](https://images.topperlearning.com/topper/tinymce/cache/9def51c14da0e23969df8e55534c581c.png)
Thus, the full load primary current, I1 = 12 A
Answered by Shiwani Sawant | 21 Apr, 2020, 15:21: PM
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