please derive the equation v*v=u*u+2as for me i am really confused
Asked by meghana.omprakash | 29th Oct, 2015, 09:33: PM
Consider the velocity–time graph of a body with initial velocity ‘u’ at point A.
It has uniform acceleration from A to B because its velocity changes uniformly in time ‘t’. After time t, its final velocity is ‘v’.
In the graph, u = OA, v = CB, t = OC.
We draw perpendicular CB from point C and draw AD parallel to OC. Also, BE is the perpendicular from B to OE.
Third equation of motion: v2 = u2 + 2as
The distance travelled is equal to the area of the figure OABC. Now, OABC is a trapezium.
Answered by Faiza Lambe | 30th Oct, 2015, 08:30: AM
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