CBSE Class 11-science Answered
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![question image](https://images.topperlearning.com/topper/new-ate/topr_187203396465339410P10.jpeg)
Asked by Prashant DIGHE | 22 Apr, 2020, 22:48: PM
when train starts from rest , moves with uniform acceleration a and attains maximum speed v , then we have
v2 = 2 a S1 ......................(1)
time taken t to attain maximum speed , t1 = v/a ....................(2)
where S1 is distance travelled
After attaining maximum speed , moves with retardation a and comes to rest after travelling a distance S2 .
Then we have, v2 = 2 a S2...............(3)
time taken t to come to rest , t2 = v/a ...................(4)
Total distance travelled , S = S1 + S2 = ( v2 / 2a ) + ( v2 / 2a ) = ( v2 / a ) ................(5)
Total time travelled , t = t1 + t2 = (2v)/a .................. (6)
using eqn.(5), we rewrite eqn.(6) as , ![begin mathsize 14px style t space equals space 2 space square root of S over a end root end style](https://images.topperlearning.com/topper/tinymce/cache/1590cb549a84b5ee312e285d9ac6bce9.png)
![begin mathsize 14px style t space equals space 2 space square root of S over a end root end style](https://images.topperlearning.com/topper/tinymce/cache/1590cb549a84b5ee312e285d9ac6bce9.png)
maximum speed , ![begin mathsize 14px style v space equals space square root of a space S end root end style](https://images.topperlearning.com/topper/tinymce/cache/8a783540524db654480253367ef90b5f.png)
![begin mathsize 14px style v space equals space square root of a space S end root end style](https://images.topperlearning.com/topper/tinymce/cache/8a783540524db654480253367ef90b5f.png)
Answered by Thiyagarajan K | 23 Apr, 2020, 08:47: AM
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