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CBSE Class 12-science Answered

Please answer below question from 2023 board paper:  
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Asked by prachis14 | 06 Mar, 2023, 04:49: PM
answered-by-expert Expert Answer

Q. In a single-slit diffraction experiment, the width of the slit is halved. The width of the central maximum, in the diffraction pattern, will become:

(a) half

(b) twice

(c) four times

(d) one-fourth

Solution:

Correct option - b: twice

In single-slit diffraction, if the width of the slit is reduced to half of its initial value, the width of the central maximum in the diffraction pattern will become twice. This is due to the fact that the width of the central maximum is inversely proportional to the width of the slit.

x equals fraction numerator lambda D over denominator d end fraction

where x is the width of the central maximum in a single slit diffraction, D is the distance between the slit and the screen, is the light wavelength, and d is the slit width. 

Hence, when the slit's width is redacted to half, the central maximum expands, resulting in a doubling of its width.

Answered by Jayesh Sah | 06 Mar, 2023, 05:42: PM
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