Request a call back

A parallel beam of light of wavelength 600 nm is incident normally on a slit of width 0.2 mm. If the resulting diffraction pattern is observed on a screen 1 m away, find the distance of (i) First minimum, and (ii) Second maximum, from the central maximum.
Asked by suman.sh01 | 21 May, 2022, 11:09: AM
First minimum occurs at angular position θ = λ /a

where λ is wavelength of light used , a is slit width

First minimum occurs at angular position θ = ( 600 × 10-9 ) / ( 2 × 10-4 )

First minimum occurs at angular position θ =  3 × 10-3 rad

Let D be the distance between slit and screen.

Distance of first minimum from central maximum = ( D θ ) = 1 × 3 × 10-3 m = 3 mm

--------------------------------------------
First maximum occurs at angular position θ = (3/2) (λ /a)

First maximum occurs at angular position θ = (3/2) ( 600 × 10-9 ) / ( 2 × 10-4 )

First maximum occurs at angular position θ  4.5 × 10-3 rad

Distance of first maximum from central maximum  = ( D θ ) = 1 × 4.5 × 10-3 m = 4.5 mm

Answered by Thiyagarajan K | 21 May, 2022, 04:43: PM

## Concept Videos

CBSE 12-science - Physics
Asked by suman.sh01 | 21 May, 2022, 11:09: AM
CBSE 12-science - Physics
Asked by arjunsah797 | 14 May, 2022, 01:34: PM
CBSE 12-science - Physics
Asked by sirib942254 | 04 Aug, 2021, 08:30: PM
CBSE 12-science - Physics
Asked by ramdasiyogesh2001 | 12 Mar, 2021, 12:47: AM
CBSE 12-science - Physics
Asked by Abhineet | 26 Nov, 2019, 02:04: AM