my question is from topic gravitation,,, CALCULATE THE HEIGHT OF COMMUNICATION SATELLITE.GIVEN THAT G=6.67*10 RAISE TO THE POWER-11 Nm square/kg square,,M=6*10 RAISE TO THE POWER 24KG,,R=6400 KM .. ANS GIVEN TO THIS QUESTION IS 35.9*10RAISE TO THE POWER 6 . PLEASE EXPLAIN HOW?

Gravitational force = Centripetal force

GMm/r² = mV²/r

Now V = 2πr/T

GMm/r² = m(2πr/T)²/r

GM/r = (2πr/T)²

r³ = (R + h)³ = GMT²/(4π²)

For communication satellite T = 24 hrs = 24x 3600 s

r³ = (R + h)³ = 6.67x10^-11x6x10²⁴(24x 3600)²/(4π²) = 7575046127.63x 10¹³ m³

 r = 4231.18 x 10⁴ m = 42312 km

r = R + h = 42312 km

h = 42312 - 6400 = 35912 km = 35.9 x 10⁶ m

Regards,

Team,

TopperLearning.