moment of force

Since cross sectional area is directly propotional to the diameter squared, and stress is force per area,

the forces in two wires are related as,

F_A = 4F_S

Also the rod is rotational equilibrium, hence if the mass m has to be suspended at a distance x from steel wire,

F_S x = F_A ( 1.05 - x)   ... (1)

 x = 4( 1.05 - x)  

x = 0.84 m from steel wire.

regards,

Team,

TopperLearning.