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CBSE Class 10 Answered

In the figure, TA and TB are tangents to the circle, centre O, at A and B respectively and OTB = 31o. Find TAB.
Asked by Topperlearning User | 05 Oct, 2017, 09:07: AM
answered-by-expert Expert Answer

OTA = OTB = 31o (Tangents from an external point are equally inclined)

TA = TB TAB = TBA (Base angles of isosceles triangle)
TAB + TBA + ATB = 180o    (angle sum of a triangle)
TAB + TBA + 31o + 31o =180o
2 TAB = 118o
TAB = 59o.
Answered by | 05 Oct, 2017, 11:07: AM

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