In a reaction of magnesium with HCl if 2.24 litre of H2 is obtained at STP the mass of the other product will be what

Asked by pamaurya76 | 27th Aug, 2020, 05:06: PM

Expert Answer:

Mg space plus space 2 HCl space rightwards arrow space MgCl subscript 2 space plus space straight H subscript 2
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space fraction numerator 2.24 over denominator 22.4 end fraction
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0.1
According space to space stoichiometry comma space
1 space mole space of space MgCl subscript 2 space end subscript space is space formed space when space 0.1 space mole space is space formed.
So comma space MgCl subscript 2 space is space formed space equals space 2.24 space straight L
Mass of MgCl =Moles of MgCl2 * Molecular Mass=  0.1(95)=9.5 g

Answered by Ravi | 28th Aug, 2020, 11:04: AM