In 1 columb of charge how many no. of electrons are present:
6*10^18 or 6.25*10^18............
Asked by devyanipathak99 | 28th Jun, 2014, 01:46: PM
We know that the charge of an electron, e = 1.6 × 10−19 C
Total charge Q= 1 C
Q = n e,
Where Q is the charge , n the number of electrons and e the charge of an electron.
n = Q / e
= 1 C / 1.6 × 10−19 C
=0.625 × 10 -19
= 6.25 × 1018
Therefore the number of electrons constituting one coulomb of charge = 6.25 × 1018
On rounding this can be written approximately as 6 × 1018
Answered by Jyothi Nair | 29th Jun, 2014, 02:51: PM
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