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if the ratio of the specific heats of steam is 1.33 and R=8312j/k mole k the molar heat capacities of steam at constant pressure and constant volume is
Asked by ghrushi3 | 02 Nov, 2023, 10:05: PM
answered-by-expert Expert Answer
Ratio of specific heats = begin mathsize 14px style C subscript P over C subscript v space equals space 1.33 end style
Where Cp is constant pressure specific heat , Cv is constant volume specific heat .
 
Hence we get begin mathsize 14px style C subscript p space equals space 1.33 space C subscript v end style ...............................(1)
 
Cp , Cv and universal gas constant R are related as
 
begin mathsize 14px style C subscript p space minus space C subscript v space equals space R space equals space 8312 space space J space divided by space left parenthesis space k m o l e space K space right parenthesis end style .................................(2)
 
From eqn. (1) and eqn.(2) , we get
 
begin mathsize 14px style left parenthesis 1.33 space minus space 1 right parenthesis space C subscript v space equals space 8312 space space J space divided by space left parenthesis space k m o l e space K space right parenthesis end style
 
Hence , we get ,  Cv = 8312 / 0.33  J / ( kmole K ) = 25188 J / (kmole K )
 
From eqn.(1) ,  Cp = 33500 J/ (kmole K )
Answered by Thiyagarajan K | 02 Nov, 2023, 11:16: PM
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