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Asked by manvirsingh2242 | 18 Jun, 2022, 18:27: PM
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Carbon-di-oxide is non-linear tri-atomic molecule that has 6 degrees of freedom
( 3 translation + 3 rotation )
 
Constant volume specific heat Cv of carbon-di-oxide gas is given as
 
Cv = ( 6/2) R = 3 R
 
where R is universal gas constant
 
Constant pressure specific heat Cp of carbon-di-oxide gas is given as
 
Cp = Cv + R = 4 R
 
Change in entropy ( ΔS )v  for isochoric process ( constant volume ) is given as
 
( ΔS )v = n Cv ln( Tf / Ti )
 
where n is number of moles , Tf is final absolute temperature and Ti is absolute temperature
 
( ΔS )v =  3 R  ln( 3 ) = 3 × 8.314 × ln(3) = 27. 4 J / K
 
Change in entropy ( ΔS )p  for isobaric process ( constant pressure ) is given as
 
( ΔS )p = n Cp ln( Tf / Ti )
 
( ΔS )p =  4 R  ln( 3 ) = 4 × 8.314 × ln(3) = 36.5 J / K
Answered by Thiyagarajan K | 18 Jun, 2022, 20:47: PM
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