if momentum increase 50% what is increase in kinetic energy?

Asked by  | 2nd Sep, 2009, 09:00: PM

Expert Answer:

Pf = 1.5Pi

Ekf = Pf2/2m

= 1.5Pi2/2m

= 2.25Pi2/2m

= 2.25Eki

Percentage increase in kinetic energy = (Ekf - Eki)x100/Eki = 125%


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Answered by  | 2nd Sep, 2009, 09:08: PM

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