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CBSE Class 11-science Answered

If a car at rest accelerates uniformly to a speed of 144 km/h in 20 sec, it covers a distance of:
Asked by Abhishek123pop | 14 Sep, 2019, 08:50: PM
answered-by-expert Expert Answer
Initial speed u = 0 ;  final speed v = 144 km/hr  = 144 × (5/18) = 40 m/s ;
 
acceleration a  is obtained from the formula,  " v = u + a t "  , i.e.  a = v/t = 40/20 = 2 m/s2
 
distance covered in 20 s :-  S = u t + (1/2) a t2 = (1/2)×2×20×20 = 400 m
Answered by Thiyagarajan K | 14 Sep, 2019, 09:11: PM
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