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CBSE Class 11-science Answered

How many moles of Al2O3 will be formed when a mixture of 5.4g Al and 3.2g O2 is heated?

Kindly provide the answer.

Asked by tps.mjmdr | 28 May, 2018, 10:04: PM
Expert Answer
Given colon space

Mass space of space Al space equals space 5.4 space straight g

Mass space of space straight O subscript 2 space equals space 3.2 space straight g.

Balanced space equation colon

4 Al space plus space 3 space straight O subscript 2 space space rightwards arrow space 2 Al subscript 2 straight O subscript 3

Now comma

Moles space of space Al space equals space fraction numerator Mass space over denominator Molar space mass end fraction space space

space space space space space space space space space space space space space space space space space space equals space fraction numerator 5.4 over denominator 26.98 end fraction

Moles space of space Al space space equals space 0.2 space mol

Moles space of space straight O subscript 2 equals space fraction numerator 3.2 over denominator 32 end fraction

Moles space of space straight O subscript 2 space equals space 0.1 space mol

Now comma space space to space find space the space limliting space agent space divide space moles space of space reactants space by space stoichiometric space coefficients

For space straight O subscript 2 space equals space fraction numerator 0.1 over denominator 3 end fraction space space space

space space space space space space space space space space space space equals space 0.033

For space Al space equals fraction numerator 0.2 over denominator 2 end fraction

space space space space space space space space space space space equals space space 0.05

As space value space of space straight O subscript 2 space is space less space than space Al comma space straight O subscript 2 space is space the space limiting space agent.
From space reaction colon
The space mole space of space straight O subscript 2 space colon space Moles space of space space Al subscript 2 straight O subscript 3
space space space space space space space space space space space space space space space space space space space space space space 3 space colon space 2
therefore space space space space space space space space space space space space space space space space 0.1 space colon space straight x

space space space space space space space space space space space space space space space space space straight x space equals space space 0.066 space mol space of space space Al subscript 2 straight O subscript 3
Moles of Al2O3 formed are 0.066 mol.
Answered by Varsha | 29 May, 2018, 10:38: AM
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