how many L of water will have to be added to 1125 l of 45% solution of acid so that resulting mix.

Asked by  | 22nd Jul, 2008, 04:13: PM

Expert Answer:

amount of acid will remain same in both the solution , but its % changes

initially amount of acid = 1125*0.45

let x L water is added then its acid % will be (1125*0.45) / (1125+x)

it should lie between 25% to 30%

.25 (1125*0.45) / (1125+x) .3

on solving this we get 562.5 x 900

Answered by  | 12th Sep, 2008, 04:19: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.