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Asked by harshilthakkarhhhhhh | 21 May, 2020, 04:37: PM
Option (C) is correct.

Given:

Volume of H2 = 12 L

=
= 0.54 mol

Volume of Cl2 = 11.2 L

=
= 0.5 mol

The reaction is

H2 +  Cl2 → 2HCl

1       1          2

1 mole of H2 combines with 1 mol of Cl2 to form 2 mol of HCl

Cl2 is the limiting reagent.

so 0.5 mol of Cl2 will give 1 mol of HCl

1 mol of HCl is 22.4 L of HCl

So, H left = 12- 11.2 = 0.8 L

HCl formed will be = 22.4 L
Answered by Varsha | 22 May, 2020, 06:09: PM

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