Asked by harshilthakkarhhhhhh | 21st May, 2020, 04:37: PM
Option (C) is correct.
Volume of H2 = 12 L
= 0.54 mol
Volume of Cl2 = 11.2 L
= 0.5 mol
The reaction is
H2 + Cl2 → 2HCl
1 1 2
1 mole of H2 combines with 1 mol of Cl2 to form 2 mol of HCl
Cl2 is the limiting reagent.
so 0.5 mol of Cl2 will give 1 mol of HCl
1 mol of HCl is 22.4 L of HCl
So, H2 left = 12- 11.2 = 0.8 L
HCl formed will be = 22.4 L
Answered by Varsha | 22nd May, 2020, 06:09: PM
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