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CBSE Class 11-science Answered

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Asked by harshilthakkarhhhhhh | 21 May, 2020, 04:37: PM
Expert Answer
Option (C) is correct.
 
Given:
 
Volume of H2 = 12 L
 
                    = fraction numerator 12 over denominator 22.4 end fraction
                    = 0.54 mol
 
 
Volume of Cl2 = 11.2 L
 
                    = fraction numerator 11.2 over denominator 22.4 end fraction
                    = 0.5 mol                   
 
The reaction is
 
  H2 +  Cl2 → 2HCl
 
 1       1          2
 
1 mole of H2 combines with 1 mol of Cl2 to form 2 mol of HCl
 
Cl2 is the limiting reagent.
 
so 0.5 mol of Cl2 will give 1 mol of HCl
 
1 mol of HCl is 22.4 L of HCl
 
So, H left = 12- 11.2 = 0.8 L
 
HCl formed will be = 22.4 L
Answered by Varsha | 22 May, 2020, 06:09: PM
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