find the value of k for which one root of the quadratic equation kx²-14x+8=0 is 2

Asked by Sendmailforsam | 9th Dec, 2018, 06:48: PM

Expert Answer:

kx2 - 14x + 8 = 0
According to the question,
Put x = 2
k × 22 - 14 × 2 + 8 = 0
4k - 28 + 8 = 0 
4k = 20
k = 5

Answered by Sneha shidid | 9th Dec, 2018, 07:18: PM

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