Find the mass of caco3 which is used for formation of co2 when dil. HCL is added
Asked by sonivivek050 | 7th Jul, 2017, 04:43: PM
The reaction of CaCO3 with dil HCl can be represented as follows:
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
From the reaction, 1 mole of calcium carbonate is required to react with 2 moles of hydrochloric acid to produce 1 mole of carbon dioxide.
Molar mass of:
CaCO3 = 100.09 g
HCl = 36.5 g
CO2 = 44.01 g
Hence, 100.09 g of calcium carbonate is required to produce 44.01 g of CO2.
Answered by Prachi Sawant | 7th Jul, 2017, 06:48: PM
- 0.315g of organic compound gave on combustion 0.4131g of water and 0.6732g of carbon dioxide calculate the percentage of carbon and hydrogen
- IS ALL PHYSICAL QUANTITIES WHICH ARE MEASUREBLE ARE MATTER OR NON MATTER?
- 0.38g of NaOH is dissolved in water to prepare 50 ml solution. calculate the molarity of the solution
- molecular mass
- 324g of 20% by mass of Ba(OH)2 solution
- what is molecular mass?
- How many gram of nh3 will be produce when 50g N2 react with h2
- what is mole
- In a reaction of magnesium with HCl if 2.24 litre of H2 is obtained at STP the mass of the other product will be what
- 5g of marble was added to 100 c.c of 0.2 M HCl. What volume of CO2 measured at STP will be evolved in the above reaction
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number