CBSE Class 12-science Answered

Answer : Let P (0, 2, 3) be the point whose image is to be determined.

Draw perpendicular from P to the given line which cuts the line L, which is its foot of perpendicular.

Then, image of P will be in the downward direction and at the same distance from L as P.

Let P' (x ₁, y ₁, z ₁) be the image of point P. Then we will find the values of x ₁, y ₁, z ₁.

Then,

Given line is

=>  (x+3) / 5 =  (y-1)/2  =  (z+4)/3  =t (let)

=> x = 5t -3 , y = 2t+1 , z= 3t - 4

i.e., the co-ordinate of any general point which lies on the given line is ( 5t -3 , 2t+1 , 3t - 4).

? Co-ordinate of L are ( 5t -3 , 2t+1 , 3t - 4). 

Now,

Direction ratio's of PL will be

 5t -3 -0 , 2t+1-2 , 3t - 4-3

= 5t - 3 , 2t -1 , 3t-7

Also,

Direction ratio's of given line are 5, 2, 3.

But, PL is perpendicular to the given line.

=> 5(5t - 3) +2( 2t -1 ) +3 ( 3t-7) =0

=> 38t = 38 

=> t = 1

? Co-ordinate of L are (2, 3, -1)

Now,

L is the mid point of PP',

By mid point formula

=> (0 + x₁ )/2 = 2 , (2+ y₁)/2 =3 , (3+ z₁)/2 = -1

 =>  x₁ = 4 ,  y₁ =4 ,  z₁ = -5 

Hence, the image of (0, 2, 3) is (4, 4, -5).