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CBSE Class 12-science Answered

Find the angle between two lines whose directions cosines are given by l+m+n=0 and l^2+m^2-n^2=0.[**WITHOUT USING THEOREMS OF VECTOR**]
Asked by arjunsah797 | 02 May, 2022, 09:30: AM
answered-by-expert Expert Answer
Given direction cosines are 
l+m+n = 0 ... (i)
l2 + m2 - n2 = 0 ... (ii)
From (i), we get, n = -(l+m)
Putting n in (ii)
l2 + m2 - (l+m)2 = 0
l2 + m2 - l2 - m2 - 2lm = 0
2lm = 0
Therefore, l = 0 or m = 0
Put l = 0 in (i), we get, n = -m
So, dorection ratios are (l, m, n) = (0, 1, -1)
Put m = 0 in (i), we get, n = -l
So, direction ratios are (l, m, n) = (1, 0, -1)
straight b with rightwards arrow on top subscript 1 times straight b with rightwards arrow on top subscript 2 equals open parentheses 0 comma space 1 comma space minus 1 close parentheses times left parenthesis 1 comma space 0 comma space minus 1 right parenthesis space equals space 0 plus 0 plus 1 space equals space 1
open vertical bar straight b with rightwards arrow on top subscript 1 close vertical bar equals square root of 2
open vertical bar straight b with rightwards arrow on top subscript 2 close vertical bar equals square root of 2
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rightwards double arrow straight theta equals straight pi over 3
Answered by Renu Varma | 02 May, 2022, 11:16: AM
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