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CBSE Class 11-science Answered

Find the distance between the lines 9x + 40y - 20 = 0 and 9x + 40 y + 103 = 0

Asked by Topperlearning User | 29 Apr, 2014, 03:24: PM
Expert Answer

9 x minus 40 y minus 20 equals 0 space a n d space 9 x plus 40 y plus 103 equals 0 space h a v e space e q u a l space s l o p e s comma space t h e r e f o r e space b o t h space t h e space l i n e s space a r e space p a r a l l e l.

d i s tan c e equals open vertical bar fraction numerator c subscript 1 minus c subscript 2 over denominator square root of A squared plus B squared end root end fraction close vertical bar equals open vertical bar fraction numerator minus 20 minus 103 over denominator square root of 9 squared plus 40 squared end root end fraction close vertical bar equals 123 over 41 equals 3

T h u s comma space t h e space d i s tan c e space b e t w e e n space t h e space g i v e n space l i n e s space i s space 3 space u n i t s.

Answered by | 29 Apr, 2014, 05:24: PM
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