CBSE Class 11-science Answered
12th sum.plz sry i earlier wrote 11th
But ita 12th
![question image](https://images.topperlearning.com/topper/new-ate/317332453247138173rps20181007143016.jpg)
Asked by lovemaan5500 | 08 Oct, 2018, 17:06: PM
x + y - 5 = 0 ......(i)
3x - 2y + 7 = 0.....(ii)
Find perpendicular distance of point P(x, y) from the lines we get
d1 =
and d2 = ![begin mathsize 16px style fraction numerator open vertical bar 3 straight x minus 2 straight y plus 7 close vertical bar over denominator square root of 13 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/7cce98c6d9709b0eeeefc276245a47af.png)
![begin mathsize 16px style fraction numerator open vertical bar straight x plus straight y minus 5 close vertical bar over denominator square root of 2 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/a68354bb1a919d1c7a9f9b000ba7a641.png)
![begin mathsize 16px style fraction numerator open vertical bar 3 straight x minus 2 straight y plus 7 close vertical bar over denominator square root of 13 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/7cce98c6d9709b0eeeefc276245a47af.png)
d1 + d2 = 10
Using this solve further we get
![begin mathsize 16px style open parentheses square root of 13 plus 3 square root of 2 close parentheses straight x plus open parentheses square root of 13 minus 2 square root of 2 close parentheses straight y plus open parentheses 7 square root of 2 minus 5 square root of 13 minus 10 square root of 26 close parentheses equals 0 end style](https://images.topperlearning.com/topper/tinymce/cache/d87f5ec318fd95e00c4de864cc15c9d0.png)
Similarly we can obtain this equation of line for any signs of x + y - 5 = 0 and 3x - 2y + 7 = 0
Thus point P must move on a line.
Answered by Sneha shidid | 10 Oct, 2018, 09:46: AM
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