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CBSE Class 11-science Answered

  find the angle between the vectors Ä= i^ -2j^ + 3k^ and b vector = -i^ + 2j^ + 3k^  
Asked by kapilkulhari | 24 Sep, 2019, 09:02: AM
answered-by-expert Expert Answer
If angle between vectors a and b is θ , then we have
begin mathsize 14px style cos theta space equals space fraction numerator a with rightwards arrow on top times b with rightwards arrow on top over denominator open vertical bar a with rightwards arrow on top close vertical bar space open vertical bar b with rightwards arrow on top close vertical bar end fraction end style
a = i - 2j + 3k  ,  |a| = ( 1+4+9)1/2 = (14)1/2
 
b = -i +2j +3k ,  |b| = ( 1+4+9)1/2 = (14)1/2
 
a.b = -1 -4 +9 = 4
 
hence cosθ = 4/13 ,  θ = cos-1(4/14) = 73°
Answered by Thiyagarajan K | 24 Sep, 2019, 10:13: AM
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