Explain the structure of Diborane and banana bonds?

Asked by  | 23rd Feb, 2013, 07:24: AM

Expert Answer:

In diborane four terminal B-H bonds are two centre - two electron bonds. Two bridge B ? H ? B bonds (or banana bonds) are three centre - two electron bonds (shown in figure).

2 boron and 4 terminal hydrogen atoms (Ht) lie in one plane, while the other two bridging hydrogen atoms (Hb) lie in a plane perpendicular to the plane of boron atoms. Again, of the two bridging hydrogen atoms, one H atom lies above the plane and the other lies below the plane. The terminal bonds are regular two-centre two-electron (2c – 2e–) bonds, while the two bridging (B–H–B) bonds are three-centre two-electron (3c – 2e–) bonds.

Answered by  | 23rd Feb, 2013, 05:15: PM

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