Plz explain me all the concepts being applied here,thanks

Asked by vishakhachandan026 | 12th Jun, 2019, 09:20: AM

Expert Answer:

(i)N(CH3)3 have one lone pair an due to +I effect of  CH3 it donates elecron so it is an Lewis base. B(CH3) is not a lewis acid because Boron is not electron deficient due to electron donating group CH3.
 
(ii)H3BO3 is Lewis acid here Boron is eletron defficient so it gains electron and behaves as Lewis acid, and C2H5OH is lewis base so interaction between these two compouds be like-      
                    straight H subscript 3 BO subscript 3 plus 3 straight C subscript 2 straight H subscript 5 OH rightwards arrow straight B left parenthesis straight C subscript 2 straight H subscript 5 straight O right parenthesis subscript 3 plus 3 straight H subscript 2 straight O
 
(iii) Ammonia ion is formed by protonation of ammonia.
                         NH subscript 3 plus straight H to the power of plus rightwards arrow NH subscript 4 to the power of plus
(iv)BF3 is a lewis acid and NHis lewis base.    
                   BF subscript 3 plus NH subscript 3 rightwards arrow left square bracket straight B left parenthesis NH subscript 3 right parenthesis straight F subscript 3 right square bracket
 
So (ii),(iii),(iV) are correct.

Answered by Ravi | 12th Jun, 2019, 02:47: PM