Request a call back

do it step by step with reasons by side
Asked by ashwinikumar59 | 08 May, 2010, 06:54: AM

Dear Student

y=(ax + b)n

(y+y)-y=[a(x+x)+b]n - (ax + b)n

[(y+y)-y]/(x)=([a(x+x)+b]n - (ax+b)n)/(x)

Applying limits on both sides with x approaching to zero, will give the value of dy/dx for

x0 y/ x = dy/dx.

x0y/x=x0 (ax+b)n ([(1+a.x/(ax+b))n - 1])/x

Expanding using Binomial, and ignoring higher order terms of x, for x is approaching to zero, and hence is very small.

=x (ax+b)n [1 + n(a.x/(ax+b))-1]/x

=x0 (ax+b)n n(a.x/(ax+b))/x

dy/dx = n.a.(ax+b)n-1

Regards Topperlearning.

Answered by | 29 May, 2010, 12:00: PM

## Application Videos

CBSE 11-science - Maths
Asked by bangtan7hybe | 18 Sep, 2022, 06:36: PM
CBSE 11-science - Maths
Asked by sakshirana374 | 24 Jul, 2022, 05:39: PM
CBSE 11-science - Maths
Asked by jaishrisayam68 | 22 Jul, 2022, 05:30: PM
CBSE 11-science - Maths
Asked by drvsam595 | 21 Jul, 2022, 05:32: PM
CBSE 11-science - Maths
Asked by simrangurdasani05 | 17 Jul, 2022, 03:39: AM
CBSE 11-science - Maths
Asked by ibcmw4 | 16 Jul, 2022, 08:14: PM