CBSE Class 11-science Answered
derive a relation of equation of motion by calculus method
Asked by anikettyagi777 | 17 Feb, 2018, 21:21: PM
(1) rate of change of velocity = acceleration.
Let v be the velocity and a is acceleration. Then mathematically ![begin mathsize 12px style fraction numerator d v over denominator d t end fraction space equals space a end style](https://images.topperlearning.com/topper/tinymce/cache/3febc936b391c86d0f3f976fad66d917.png)
![begin mathsize 12px style fraction numerator d v over denominator d t end fraction space equals space a end style](https://images.topperlearning.com/topper/tinymce/cache/3febc936b391c86d0f3f976fad66d917.png)
![begin mathsize 12px style d v space equals space a space d t integral subscript u superscript v d v space equals space integral subscript 0 superscript t a space d t v space minus space u space equals space a space t space semicolon space w h e r e space u space i s space i n i t i a l space v e l o c i t y space a n d space v space i s space f i n a l space v e l o c i t y h e n c e space v space equals space u plus a space t end style](https://images.topperlearning.com/topper/tinymce/cache/09b50b39062fbd66e718708234d6287a.png)
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(2) rate of displacement = velocity
mathematically ![begin mathsize 12px style fraction numerator d s over denominator d t end fraction space equals space v semicolon end style](https://images.topperlearning.com/topper/tinymce/cache/b901fed6a51b656a7c28d19f84fda3e8.png)
![begin mathsize 12px style fraction numerator d s over denominator d t end fraction space equals space v semicolon end style](https://images.topperlearning.com/topper/tinymce/cache/b901fed6a51b656a7c28d19f84fda3e8.png)
![begin mathsize 12px style w h e r e space d s space i s space a space s m a l l space d i s p l a c e m e n t space i n space t i m e space d t d s space equals space v space d t space equals space open parentheses u space plus space a space t close parentheses space d t space equals space u space d t space plus space a space t space d t integral subscript 0 superscript S d s space equals space integral subscript 0 superscript t u space d t space plus space integral subscript 0 superscript t space a space t space d t S space equals space u space t space plus space 1 half a space t squared end style](https://images.topperlearning.com/topper/tinymce/cache/99f87a57b2bc3ac816454b75a48fadf9.png)
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Let distance travelled is S in time t. Let initial velocity is u and final velocity is v.
distance = average velocity × time
![begin mathsize 12px style S space equals space fraction numerator v plus u over denominator 2 end fraction cross times t sin c e space v space equals space u plus a t comma space w e space s u b s t i t u t e space t space equals space fraction numerator v minus u over denominator a end fraction space i n space t h e space a b o v e space e q u a t i o n t h e n space S space equals space fraction numerator v plus u over denominator 2 end fraction cross times fraction numerator v minus u over denominator a end fraction space equals space fraction numerator open parentheses v squared space minus space u squared close parentheses over denominator 2 a end fraction h e n c e space v squared space equals space u squared minus 2 space a space S end style](https://images.topperlearning.com/topper/tinymce/cache/2ad7e165f6ae30fddb7382285a3ee144.png)
Answered by Thiyagarajan K | 17 Feb, 2018, 21:59: PM
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