CBSE Class 11-science Answered
Calculate the pH of a solution that has a [OH1-] = 1 X 10-5 M
Asked by Topperlearning User | 16 Jun, 2016, 05:21: PM
Expert Answer
First determine pOH = -log[OH- ] = -log [1 X 10-5 ] = 5
Now we know, Ionic product of water = pH + pOH = 14
pH + 5 = 14 Or, pH = 14 -5 = 9
Answered by | 16 Jun, 2016, 07:21: PM
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