CBSE Class 11-science Answered

Calculate the number of Cl- ion in 100 ml of the solution which is formed by mixing of 200 ml of 2M NaCl(aq) , 800 ml 1M MgCl2 (aq) solution and 1 litre 5.3× 10^ -4 M CCl4 (aq) solution ?

Asked by arunavamitra50 | 29 May, 2019, 12:42: PM

Expert Answer

CCl₄ is a nonpolar compound which does not release Cl ion in solution.

Only NaCl and MgCl₂ will release Cl ion.

NaCl, MgCl₂ and CCl₄ will have ratio of

200: 800 : 1000

1:4:5

When we are taking 100ml sample,

ratio will be same because mixture is uniformly distributed

So i 100ml, NaCl will have=10 ml

MgCl₂ will have=40 ml

CCl₄will have=50ml

Moles space of space NaCl equals Molarity cross times Volume left parenthesis in space straight l right parenthesis space space space space space space space space space space space space space space space space space space space space space space equals 2 cross times 10 over 100 space space space space space space space space space space space space space space space space space space space space space space equals 0.2 space moles Moles space of space MgCl subscript 2 space equals space 1 cross times 40 over 100 space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.4 space moles 1 space moles space of space NaCl space releases space 1 space mole space of space Cl to the power of minus space ion. So space 0.2 space moles space of space NaCl space will space give equals 0.2 space moles space of space Cl to the power of minus space ions 1 space mole space of space MgCl subscript 2 space releases equals space 2 space moles space of space Cl to the power of minus space ions So space 0.2 space mole space of space space MgCl subscript 2 space will space release equals 0.4 space moles space of space Cl to the power of minus space ions Total space moles space of space Cl to the power of negative space end exponent space ions equals 0.6 space moles Number space of space Cl to the power of negative space space end exponent space ions equals 0.6 cross times 6.022 cross times 10 to the power of 23 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 3.613 cross times 10 to the power of 23 space space space space space

Answered by Ravi | 30 May, 2019, 05:50: PM

CBSE Class 11-science Answered

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